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General => Off Topic => Topic started by: ARTgames on September 09, 2009, 01:15:36 AM

Title: 4 challenge
Post by: ARTgames on September 09, 2009, 01:15:36 AM
some one a long time ago had a topic that was something like you could get ever number from 1 to 100 using 4 in some way. does any one here still rmb the rules?
Title: Re: 4 challenge
Post by: DragonReaper on October 13, 2009, 03:52:20 AM
I did it at school once in maths, you have to get every number from 1-100 using 4 four's and maths symbols
eg, 52= 44+4+4
Title: Re: 4 challenge
Post by: Trogdor on October 13, 2009, 04:49:52 AM
I've never heard of this game before. At first I thought it would be impossible, as you're only working with an even number, 4, and eliminates the possibilities of odd numbers. I thought about it for some time, and then realized 4/4 = 1, which gives you an odd number to work with, thus making it quite simple. I'm sure there would be some limitation on the amount or type of math symbols you could use, otherwise it would be a simple matter of 1+1+4+1 etc.

I'm only up to College Algebra, so there might be more ways to solve this.  ;)
Title: Re: 4 challenge
Post by: flashmaniac on October 13, 2009, 05:28:53 AM
I'm pretty sure there's another variation of this but it's with your year of birth. For example: 1994. I'm not sure if it works with all years but I have seen it done.
Title: Re: 4 challenge
Post by: Red October on October 13, 2009, 06:09:40 AM
My attempt (all checked with google):

1) (4/4)*(4/4)
2) 4/(4+4)*4
3) -4/4^2*4+4
4) (sqrt 4^3)/4*4-4
5) 4*4/4^2+4
6) (sqrt 4)/4*4+4
7) -4/4+4+4
8.) 4*4-4-4
9) 4*(sqrt 4)+4/4
10) (sqrt 4)+4^2-4-4
11) -4/4+4^2-4
12) (sqrt 4^3)/4*4+4
13) 4/4+4^2-4
14) -(sqrt 4)+4^2+4-4
15) 4*4-4/4
16) 4*4-4+4
17) 4/4+4*4
18) (sqrt 4)+4^2+4-4
19) -4/4+4^2+4
20) (4/(sqrt 4))^2+4*4
21) 4/4+4^2+4
22) -(sqrt 4)+4^2+4+4

24) 4^2+4^2-4-4

26) (sqrt 4)+4^2+4+4

28) (sqrt 4^3)*4^2/4-4

30) (sqrt 4)-4+4^2+4^2
31) -4/4+4^2+4^2
32) 4^2+4^2-4+4

36) 4^2+4^2+4^2/4

40) 4^2+4^2+4+4

44) 4^2+4^2+4^2-4

52) 4^2+4^2+4^2+4

54) -(sqrt 4)+4^3-4-4

56) -4^2/4+4^3-4

59) -4/4+4^3-4
60) (sqrt 4^4)*4^2/4-4
61) 4/4+4^3-4
62) -(sqrt 4)+4^3+4-4
63) -4/4+4*4^2
64) 4*4/4*4^2

66) (sqrt 4)+4^3+4-4
67) -4/4+4^3+4
68) 4^5/4/4+4
69) 4/4+4^3+4
70) -(sqrt 4)+4^3+4+4

72) 4^3+4^2-4-4

78) (sqrt 4)-4+4^2+4^3

80) 4^3+4^2-4+4

84) (sqrt 4^7)-4^3+4^2+4

88) 4^3+4^2+4+4

92) (sqrt 4^7)-4^2-4^2-4

96) (sqrt 4^7)-4^3+4^2+4^2

100) (sqrt 4^7)-4^2-4^2+4

I got bored at this time.
Title: Re: 4 challenge
Post by: yottabyte on October 13, 2009, 08:17:06 AM
Quote from: Red October on October 13, 2009, 06:09:40 AM
My attempt (all checked with google):

numbers

I got bored at this time.

Wait, what? ???
Title: Re: 4 challenge
Post by: Mr Pwnage on October 13, 2009, 04:35:13 PM
Quote from: yottabyte on October 13, 2009, 08:17:06 AM
Quote from: Red October on October 13, 2009, 06:09:40 AM
My attempt (all checked with google):

numbers

I got bored at this time.

Wait, what? ???
For lack of better words, he just raped this topic. Nice work though...hah O_O.
Title: Re: 4 challenge
Post by: ARTgames on October 13, 2009, 07:26:15 PM
@Red October
you use other #'s than 4's. Can you do that? I think you cant. because if you could all you wold half to do is.

1) (4+4)-(4+4)+1
2) (4+4)-(4+4)+2
3) (4+4)-(4+4)+3
4) 4+(4+4+4)*0
5) (4+4)-(4+4)+5
6) (4+4)-(4+4)+6
.... ect

I think you can only use four 4s.

edit:
http://mathforum.org/ruth/four4s.puzzle.html
Title: Re: 4 challenge
Post by: Torch on October 13, 2009, 09:23:40 PM
Quote from: ARTgames on October 13, 2009, 07:26:15 PM
@Red October
you use other #'s than 4's. Can you do that? I think you cant. because if you could all you wold half to do is.

1) (4+4)-(4+4)+1
2) (4+4)-(4+4)+2
3) (4+4)-(4+4)+3
4) 4+(4+4+4)*0
5) (4+4)-(4+4)+5
6) (4+4)-(4+4)+6
.... ect

I think you can only use four 4s.

edit:
http://mathforum.org/ruth/four4s.puzzle.html
He's using exponent numbers other than 4. 4^3 is the same as saying 4*4*4. It saves space to use exponents, but isn't necessary.
Title: Re: 4 challenge
Post by: ARTgames on October 13, 2009, 10:14:10 PM
ok so i can use 4*3 because all that is is 4+4+4 >_<......


Using four 4's and any operations, try to write equations that have the numbers from 0 to 100 as the answer.


4^2+4^2+4+4 is not Using four 4's. Its using 4 4s and a 2. Its what makes it harder.

non the less the website i posted answer what i needed from this topic.
Title: Re: 4 challenge
Post by: yottabyte on October 14, 2009, 09:01:54 AM
I learn more here than I do in math class. lol
Title: Re: 4 challenge
Post by: Red October on October 14, 2009, 04:57:02 PM
Quote from: ARTgames on October 13, 2009, 10:14:10 PM
4^2+4^2+4+4 is not Using four 4's. Its using 4 4s and a 2. Its what makes it harder.

The ^2 simply means to the power of two. So in this case; 4 * 4 + 4 * 4 + 4 + 4 (so in fact I'm using 6 4's).

I was tryping to do this while not using he number 44. Here is another one I could of done for 1)

tan(4/4+44)
= tan(45)
= 1.

:)
Title: Re: 4 challenge
Post by: NotoriousM4^ on October 14, 2009, 05:27:37 PM
Quote from: Red October on October 14, 2009, 04:57:02 PM
Quote from: ARTgames on October 13, 2009, 10:14:10 PM
4^2+4^2+4+4 is not Using four 4's. Its using 4 4s and a 2. Its what makes it harder.

The ^2 simply means to the power of two. So in this case; 4 * 4 + 4 * 4 + 4 + 4 (so in fact I'm using 6 4's).

I was tryping to do this while not using he number 44. Here is another one I could of done for 1)

tan(4/4+44)
= tan(45)
= 1.

:)
(http://cache.gawker.com/assets/images/2009/02/custom_1234214353977_a_winner_is_you_1024.jpg)
Title: Re: 4 challenge
Post by: Torch on October 14, 2009, 06:45:48 PM
Quote from: Red October on October 14, 2009, 04:57:02 PM
Quote from: ARTgames on October 13, 2009, 10:14:10 PM
4^2+4^2+4+4 is not Using four 4's. Its using 4 4s and a 2. Its what makes it harder.

The ^2 simply means to the power of two. So in this case; 4 * 4 + 4 * 4 + 4 + 4 (so in fact I'm using 6 4's).

I was tryping to do this while not using he number 44. Here is another one I could of done for 1)

tan(4/4+44)
= tan(45)
= 1.

:)
But 4/4 is in that equation. There's no point.
Title: Re: 4 challenge
Post by: Mystery on October 14, 2009, 08:16:50 PM
Quote from: Torch on October 14, 2009, 06:45:48 PM
Quote from: Red October on October 14, 2009, 04:57:02 PM
Quote from: ARTgames on October 13, 2009, 10:14:10 PM
4^2+4^2+4+4 is not Using four 4's. Its using 4 4s and a 2. Its what makes it harder.

The ^2 simply means to the power of two. So in this case; 4 * 4 + 4 * 4 + 4 + 4 (so in fact I'm using 6 4's).

I was tryping to do this while not using he number 44. Here is another one I could of done for 1)

tan(4/4+44)
= tan(45)
= 1.

:)
But 4/4 is in that equation. There's no point.
You just have to have 4 everywhere in your equation. I guess to make it more confusing or something.

And I love how no one had replied to this topic before until DragonReaper bumped it, then everyone seemed to disregard that. -_-
Title: Re: 4 challenge
Post by: Red October on October 15, 2009, 02:00:26 AM
Quote from: Torch on October 14, 2009, 06:45:48 PM
Quote from: Red October on October 14, 2009, 04:57:02 PM
Quote from: ARTgames on October 13, 2009, 10:14:10 PM
4^2+4^2+4+4 is not Using four 4's. Its using 4 4s and a 2. Its what makes it harder.

The ^2 simply means to the power of two. So in this case; 4 * 4 + 4 * 4 + 4 + 4 (so in fact I'm using 6 4's).

I was tryping to do this while not using he number 44. Here is another one I could of done for 1)

tan(4/4+44)
= tan(45)
= 1.

:)
But 4/4 is in that equation. There's no point.

You fail to see the point of this challenge. The challenge is to use 4 in any form to create an answer between 1 to 100.

So in the example I gave I used 4 4's to get an answer that was equal to one.
Title: Re: 4 challenge
Post by: Torch on October 15, 2009, 06:02:33 AM
You don't need to use 4 4s, you need to have equations that only contain the number 4.
Title: Re: 4 challenge
Post by: ARTgames on October 15, 2009, 08:12:54 AM
Quote from: Torch on October 15, 2009, 06:02:33 AM
You don't need to use 4 4s

Quote from: http://mathforum.org/ruth/four4s.puzzle.htmlUsing four 4's
Title: Re: 4 challenge
Post by: DragonReaper on October 17, 2009, 05:56:01 AM
Heres me trying to do the rest *fishes out old maths book*

23)(4!-sqrt4)+(4/4)
25)(sqrt4+sqrt4)!+(4/4)
27)(4!+sqrt4)+(4/4)
29)(4!+4)+(4/4)
33)didn't get this one
34)(4x4)x sqrt4)+sqrt4
35)didn't get this one
37)didn't get this one either
38)(44-4)-sqrt4
39)no gettie
41)nadda
42)44-(4-sqrt4)
43)44-(4/4)
45)44+(4/4)
46)44+(4-sqrt4)
47)(4!+4!)/4
48)(4!+4!)-(4-4)
49)(4!+4!)+(4/4)
50 44+(4+sqrt4)

4!=24(1x2x3x4) in case your wondering
For some reason my book only goes up to 50...  ::)


Title: Re: 4 challenge
Post by: Torch on October 17, 2009, 07:46:41 AM
Quote from: ARTgames on October 15, 2009, 08:12:54 AM
Quote from: Torch on October 15, 2009, 06:02:33 AM
You don't need to use 4 4s

Quote from: http://mathforum.org/ruth/four4s.puzzle.htmlUsing four 4's
Fine, your first post said "using only 4s".